Integrand size = 20, antiderivative size = 222 \[ \int \frac {x (a+b x)^{5/2}}{(c+d x)^{5/2}} \, dx=-\frac {2 c (a+b x)^{7/2}}{3 d (b c-a d) (c+d x)^{3/2}}-\frac {2 (7 b c-3 a d) (a+b x)^{5/2}}{3 d^2 (b c-a d) \sqrt {c+d x}}-\frac {5 b (7 b c-3 a d) \sqrt {a+b x} \sqrt {c+d x}}{4 d^4}+\frac {5 b (7 b c-3 a d) (a+b x)^{3/2} \sqrt {c+d x}}{6 d^3 (b c-a d)}+\frac {5 \sqrt {b} (7 b c-3 a d) (b c-a d) \text {arctanh}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{4 d^{9/2}} \]
-2/3*c*(b*x+a)^(7/2)/d/(-a*d+b*c)/(d*x+c)^(3/2)+5/4*(-3*a*d+7*b*c)*(-a*d+b *c)*arctanh(d^(1/2)*(b*x+a)^(1/2)/b^(1/2)/(d*x+c)^(1/2))*b^(1/2)/d^(9/2)-2 /3*(-3*a*d+7*b*c)*(b*x+a)^(5/2)/d^2/(-a*d+b*c)/(d*x+c)^(1/2)+5/6*b*(-3*a*d +7*b*c)*(b*x+a)^(3/2)*(d*x+c)^(1/2)/d^3/(-a*d+b*c)-5/4*b*(-3*a*d+7*b*c)*(b *x+a)^(1/2)*(d*x+c)^(1/2)/d^4
Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 10.13 (sec) , antiderivative size = 110, normalized size of antiderivative = 0.50 \[ \int \frac {x (a+b x)^{5/2}}{(c+d x)^{5/2}} \, dx=\frac {2 (a+b x)^{7/2} \left (7 c (-b c+a d)+(7 b c-3 a d) (c+d x) \sqrt {\frac {b (c+d x)}{b c-a d}} \operatorname {Hypergeometric2F1}\left (\frac {3}{2},\frac {7}{2},\frac {9}{2},\frac {d (a+b x)}{-b c+a d}\right )\right )}{21 d (b c-a d)^2 (c+d x)^{3/2}} \]
(2*(a + b*x)^(7/2)*(7*c*(-(b*c) + a*d) + (7*b*c - 3*a*d)*(c + d*x)*Sqrt[(b *(c + d*x))/(b*c - a*d)]*Hypergeometric2F1[3/2, 7/2, 9/2, (d*(a + b*x))/(- (b*c) + a*d)]))/(21*d*(b*c - a*d)^2*(c + d*x)^(3/2))
Time = 0.26 (sec) , antiderivative size = 207, normalized size of antiderivative = 0.93, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.300, Rules used = {87, 57, 60, 60, 66, 221}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {x (a+b x)^{5/2}}{(c+d x)^{5/2}} \, dx\) |
| \(\Big \downarrow \) 87 |
| \(\displaystyle \frac {(7 b c-3 a d) \int \frac {(a+b x)^{5/2}}{(c+d x)^{3/2}}dx}{3 d (b c-a d)}-\frac {2 c (a+b x)^{7/2}}{3 d (c+d x)^{3/2} (b c-a d)}\) |
| \(\Big \downarrow \) 57 |
| \(\displaystyle \frac {(7 b c-3 a d) \left (\frac {5 b \int \frac {(a+b x)^{3/2}}{\sqrt {c+d x}}dx}{d}-\frac {2 (a+b x)^{5/2}}{d \sqrt {c+d x}}\right )}{3 d (b c-a d)}-\frac {2 c (a+b x)^{7/2}}{3 d (c+d x)^{3/2} (b c-a d)}\) |
| \(\Big \downarrow \) 60 |
| \(\displaystyle \frac {(7 b c-3 a d) \left (\frac {5 b \left (\frac {(a+b x)^{3/2} \sqrt {c+d x}}{2 d}-\frac {3 (b c-a d) \int \frac {\sqrt {a+b x}}{\sqrt {c+d x}}dx}{4 d}\right )}{d}-\frac {2 (a+b x)^{5/2}}{d \sqrt {c+d x}}\right )}{3 d (b c-a d)}-\frac {2 c (a+b x)^{7/2}}{3 d (c+d x)^{3/2} (b c-a d)}\) |
| \(\Big \downarrow \) 60 |
| \(\displaystyle \frac {(7 b c-3 a d) \left (\frac {5 b \left (\frac {(a+b x)^{3/2} \sqrt {c+d x}}{2 d}-\frac {3 (b c-a d) \left (\frac {\sqrt {a+b x} \sqrt {c+d x}}{d}-\frac {(b c-a d) \int \frac {1}{\sqrt {a+b x} \sqrt {c+d x}}dx}{2 d}\right )}{4 d}\right )}{d}-\frac {2 (a+b x)^{5/2}}{d \sqrt {c+d x}}\right )}{3 d (b c-a d)}-\frac {2 c (a+b x)^{7/2}}{3 d (c+d x)^{3/2} (b c-a d)}\) |
| \(\Big \downarrow \) 66 |
| \(\displaystyle \frac {(7 b c-3 a d) \left (\frac {5 b \left (\frac {(a+b x)^{3/2} \sqrt {c+d x}}{2 d}-\frac {3 (b c-a d) \left (\frac {\sqrt {a+b x} \sqrt {c+d x}}{d}-\frac {(b c-a d) \int \frac {1}{b-\frac {d (a+b x)}{c+d x}}d\frac {\sqrt {a+b x}}{\sqrt {c+d x}}}{d}\right )}{4 d}\right )}{d}-\frac {2 (a+b x)^{5/2}}{d \sqrt {c+d x}}\right )}{3 d (b c-a d)}-\frac {2 c (a+b x)^{7/2}}{3 d (c+d x)^{3/2} (b c-a d)}\) |
| \(\Big \downarrow \) 221 |
| \(\displaystyle \frac {(7 b c-3 a d) \left (\frac {5 b \left (\frac {(a+b x)^{3/2} \sqrt {c+d x}}{2 d}-\frac {3 (b c-a d) \left (\frac {\sqrt {a+b x} \sqrt {c+d x}}{d}-\frac {(b c-a d) \text {arctanh}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{\sqrt {b} d^{3/2}}\right )}{4 d}\right )}{d}-\frac {2 (a+b x)^{5/2}}{d \sqrt {c+d x}}\right )}{3 d (b c-a d)}-\frac {2 c (a+b x)^{7/2}}{3 d (c+d x)^{3/2} (b c-a d)}\) |
(-2*c*(a + b*x)^(7/2))/(3*d*(b*c - a*d)*(c + d*x)^(3/2)) + ((7*b*c - 3*a*d )*((-2*(a + b*x)^(5/2))/(d*Sqrt[c + d*x]) + (5*b*(((a + b*x)^(3/2)*Sqrt[c + d*x])/(2*d) - (3*(b*c - a*d)*((Sqrt[a + b*x]*Sqrt[c + d*x])/d - ((b*c - a*d)*ArcTanh[(Sqrt[d]*Sqrt[a + b*x])/(Sqrt[b]*Sqrt[c + d*x])])/(Sqrt[b]*d^ (3/2))))/(4*d)))/d))/(3*d*(b*c - a*d))
3.7.92.3.1 Defintions of rubi rules used
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + 1))), x] - Simp[d*(n/(b*(m + 1))) Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d}, x] & & GtQ[n, 0] && LtQ[m, -1] && !(IntegerQ[n] && !IntegerQ[m]) && !(ILeQ[m + n + 2, 0] && (FractionQ[m] || GeQ[2*n + m + 1, 0])) && IntLinearQ[a, b, c , d, m, n, x]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + n + 1))), x] + Simp[n*((b*c - a*d)/( b*(m + n + 1))) Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d}, x] && GtQ[n, 0] && NeQ[m + n + 1, 0] && !(IGtQ[m, 0] && ( !Integer Q[n] || (GtQ[m, 0] && LtQ[m - n, 0]))) && !ILtQ[m + n + 2, 0] && IntLinear Q[a, b, c, d, m, n, x]
Int[1/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]), x_Symbol] :> Simp[ 2 Subst[Int[1/(b - d*x^2), x], x, Sqrt[a + b*x]/Sqrt[c + d*x]], x] /; Fre eQ[{a, b, c, d}, x] && !GtQ[c - a*(d/b), 0]
Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p _.), x_] :> Simp[(-(b*e - a*f))*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/(f*(p + 1)*(c*f - d*e))), x] - Simp[(a*d*f*(n + p + 2) - b*(d*e*(n + 1) + c*f*(p + 1)))/(f*(p + 1)*(c*f - d*e)) Int[(c + d*x)^n*(e + f*x)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e, f, n}, x] && LtQ[p, -1] && ( !LtQ[n, -1] || Intege rQ[p] || !(IntegerQ[n] || !(EqQ[e, 0] || !(EqQ[c, 0] || LtQ[p, n]))))
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x /Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
Leaf count of result is larger than twice the leaf count of optimal. \(749\) vs. \(2(184)=368\).
Time = 0.57 (sec) , antiderivative size = 750, normalized size of antiderivative = 3.38
| method | result | size |
| default | \(\frac {\sqrt {b x +a}\, \left (45 \ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a^{2} b \,d^{4} x^{2}-150 \ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a \,b^{2} c \,d^{3} x^{2}+105 \ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) b^{3} c^{2} d^{2} x^{2}+12 b^{2} d^{3} x^{3} \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+90 \ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a^{2} b c \,d^{3} x -300 \ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a \,b^{2} c^{2} d^{2} x +210 \ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) b^{3} c^{3} d x +54 a b \,d^{3} x^{2} \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}-42 b^{2} c \,d^{2} x^{2} \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+45 \ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a^{2} b \,c^{2} d^{2}-150 \ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a \,b^{2} c^{3} d +105 \ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) b^{3} c^{4}-48 a^{2} d^{3} x \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+316 a b c \,d^{2} x \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}-280 b^{2} c^{2} d x \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}-32 a^{2} c \,d^{2} \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+230 a b \,c^{2} d \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}-210 b^{2} c^{3} \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}\right )}{24 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}\, \left (d x +c \right )^{\frac {3}{2}} d^{4}}\) | \(750\) |
1/24*(b*x+a)^(1/2)*(45*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/ 2)+a*d+b*c)/(b*d)^(1/2))*a^2*b*d^4*x^2-150*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x +c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*a*b^2*c*d^3*x^2+105*ln(1/2*(2 *b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*b^3*c^2 *d^2*x^2+12*b^2*d^3*x^3*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+90*ln(1/2*(2*b *d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*a^2*b*c*d ^3*x-300*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b *d)^(1/2))*a*b^2*c^2*d^2*x+210*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*( b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*b^3*c^3*d*x+54*a*b*d^3*x^2*((b*x+a)*(d*x+ c))^(1/2)*(b*d)^(1/2)-42*b^2*c*d^2*x^2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2) +45*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^( 1/2))*a^2*b*c^2*d^2-150*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1 /2)+a*d+b*c)/(b*d)^(1/2))*a*b^2*c^3*d+105*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+ c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*b^3*c^4-48*a^2*d^3*x*((b*x+a)* (d*x+c))^(1/2)*(b*d)^(1/2)+316*a*b*c*d^2*x*((b*x+a)*(d*x+c))^(1/2)*(b*d)^( 1/2)-280*b^2*c^2*d*x*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)-32*a^2*c*d^2*((b* x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+230*a*b*c^2*d*((b*x+a)*(d*x+c))^(1/2)*(b*d )^(1/2)-210*b^2*c^3*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2))/((b*x+a)*(d*x+c)) ^(1/2)/(b*d)^(1/2)/(d*x+c)^(3/2)/d^4
Time = 0.49 (sec) , antiderivative size = 619, normalized size of antiderivative = 2.79 \[ \int \frac {x (a+b x)^{5/2}}{(c+d x)^{5/2}} \, dx=\left [\frac {15 \, {\left (7 \, b^{2} c^{4} - 10 \, a b c^{3} d + 3 \, a^{2} c^{2} d^{2} + {\left (7 \, b^{2} c^{2} d^{2} - 10 \, a b c d^{3} + 3 \, a^{2} d^{4}\right )} x^{2} + 2 \, {\left (7 \, b^{2} c^{3} d - 10 \, a b c^{2} d^{2} + 3 \, a^{2} c d^{3}\right )} x\right )} \sqrt {\frac {b}{d}} \log \left (8 \, b^{2} d^{2} x^{2} + b^{2} c^{2} + 6 \, a b c d + a^{2} d^{2} + 4 \, {\left (2 \, b d^{2} x + b c d + a d^{2}\right )} \sqrt {b x + a} \sqrt {d x + c} \sqrt {\frac {b}{d}} + 8 \, {\left (b^{2} c d + a b d^{2}\right )} x\right ) + 4 \, {\left (6 \, b^{2} d^{3} x^{3} - 105 \, b^{2} c^{3} + 115 \, a b c^{2} d - 16 \, a^{2} c d^{2} - 3 \, {\left (7 \, b^{2} c d^{2} - 9 \, a b d^{3}\right )} x^{2} - 2 \, {\left (70 \, b^{2} c^{2} d - 79 \, a b c d^{2} + 12 \, a^{2} d^{3}\right )} x\right )} \sqrt {b x + a} \sqrt {d x + c}}{48 \, {\left (d^{6} x^{2} + 2 \, c d^{5} x + c^{2} d^{4}\right )}}, -\frac {15 \, {\left (7 \, b^{2} c^{4} - 10 \, a b c^{3} d + 3 \, a^{2} c^{2} d^{2} + {\left (7 \, b^{2} c^{2} d^{2} - 10 \, a b c d^{3} + 3 \, a^{2} d^{4}\right )} x^{2} + 2 \, {\left (7 \, b^{2} c^{3} d - 10 \, a b c^{2} d^{2} + 3 \, a^{2} c d^{3}\right )} x\right )} \sqrt {-\frac {b}{d}} \arctan \left (\frac {{\left (2 \, b d x + b c + a d\right )} \sqrt {b x + a} \sqrt {d x + c} \sqrt {-\frac {b}{d}}}{2 \, {\left (b^{2} d x^{2} + a b c + {\left (b^{2} c + a b d\right )} x\right )}}\right ) - 2 \, {\left (6 \, b^{2} d^{3} x^{3} - 105 \, b^{2} c^{3} + 115 \, a b c^{2} d - 16 \, a^{2} c d^{2} - 3 \, {\left (7 \, b^{2} c d^{2} - 9 \, a b d^{3}\right )} x^{2} - 2 \, {\left (70 \, b^{2} c^{2} d - 79 \, a b c d^{2} + 12 \, a^{2} d^{3}\right )} x\right )} \sqrt {b x + a} \sqrt {d x + c}}{24 \, {\left (d^{6} x^{2} + 2 \, c d^{5} x + c^{2} d^{4}\right )}}\right ] \]
[1/48*(15*(7*b^2*c^4 - 10*a*b*c^3*d + 3*a^2*c^2*d^2 + (7*b^2*c^2*d^2 - 10* a*b*c*d^3 + 3*a^2*d^4)*x^2 + 2*(7*b^2*c^3*d - 10*a*b*c^2*d^2 + 3*a^2*c*d^3 )*x)*sqrt(b/d)*log(8*b^2*d^2*x^2 + b^2*c^2 + 6*a*b*c*d + a^2*d^2 + 4*(2*b* d^2*x + b*c*d + a*d^2)*sqrt(b*x + a)*sqrt(d*x + c)*sqrt(b/d) + 8*(b^2*c*d + a*b*d^2)*x) + 4*(6*b^2*d^3*x^3 - 105*b^2*c^3 + 115*a*b*c^2*d - 16*a^2*c* d^2 - 3*(7*b^2*c*d^2 - 9*a*b*d^3)*x^2 - 2*(70*b^2*c^2*d - 79*a*b*c*d^2 + 1 2*a^2*d^3)*x)*sqrt(b*x + a)*sqrt(d*x + c))/(d^6*x^2 + 2*c*d^5*x + c^2*d^4) , -1/24*(15*(7*b^2*c^4 - 10*a*b*c^3*d + 3*a^2*c^2*d^2 + (7*b^2*c^2*d^2 - 1 0*a*b*c*d^3 + 3*a^2*d^4)*x^2 + 2*(7*b^2*c^3*d - 10*a*b*c^2*d^2 + 3*a^2*c*d ^3)*x)*sqrt(-b/d)*arctan(1/2*(2*b*d*x + b*c + a*d)*sqrt(b*x + a)*sqrt(d*x + c)*sqrt(-b/d)/(b^2*d*x^2 + a*b*c + (b^2*c + a*b*d)*x)) - 2*(6*b^2*d^3*x^ 3 - 105*b^2*c^3 + 115*a*b*c^2*d - 16*a^2*c*d^2 - 3*(7*b^2*c*d^2 - 9*a*b*d^ 3)*x^2 - 2*(70*b^2*c^2*d - 79*a*b*c*d^2 + 12*a^2*d^3)*x)*sqrt(b*x + a)*sqr t(d*x + c))/(d^6*x^2 + 2*c*d^5*x + c^2*d^4)]
\[ \int \frac {x (a+b x)^{5/2}}{(c+d x)^{5/2}} \, dx=\int \frac {x \left (a + b x\right )^{\frac {5}{2}}}{\left (c + d x\right )^{\frac {5}{2}}}\, dx \]
Exception generated. \[ \int \frac {x (a+b x)^{5/2}}{(c+d x)^{5/2}} \, dx=\text {Exception raised: ValueError} \]
Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'assume' command before evaluation *may* help (example of legal syntax is 'assume(a*d-b*c>0)', see `assume?` for m ore detail
Leaf count of result is larger than twice the leaf count of optimal. 404 vs. \(2 (184) = 368\).
Time = 0.39 (sec) , antiderivative size = 404, normalized size of antiderivative = 1.82 \[ \int \frac {x (a+b x)^{5/2}}{(c+d x)^{5/2}} \, dx=\frac {{\left ({\left (3 \, {\left (b x + a\right )} {\left (\frac {2 \, {\left (b^{5} c d^{6} {\left | b \right |} - a b^{4} d^{7} {\left | b \right |}\right )} {\left (b x + a\right )}}{b^{4} c d^{7} - a b^{3} d^{8}} - \frac {7 \, b^{6} c^{2} d^{5} {\left | b \right |} - 10 \, a b^{5} c d^{6} {\left | b \right |} + 3 \, a^{2} b^{4} d^{7} {\left | b \right |}}{b^{4} c d^{7} - a b^{3} d^{8}}\right )} - \frac {20 \, {\left (7 \, b^{7} c^{3} d^{4} {\left | b \right |} - 17 \, a b^{6} c^{2} d^{5} {\left | b \right |} + 13 \, a^{2} b^{5} c d^{6} {\left | b \right |} - 3 \, a^{3} b^{4} d^{7} {\left | b \right |}\right )}}{b^{4} c d^{7} - a b^{3} d^{8}}\right )} {\left (b x + a\right )} - \frac {15 \, {\left (7 \, b^{8} c^{4} d^{3} {\left | b \right |} - 24 \, a b^{7} c^{3} d^{4} {\left | b \right |} + 30 \, a^{2} b^{6} c^{2} d^{5} {\left | b \right |} - 16 \, a^{3} b^{5} c d^{6} {\left | b \right |} + 3 \, a^{4} b^{4} d^{7} {\left | b \right |}\right )}}{b^{4} c d^{7} - a b^{3} d^{8}}\right )} \sqrt {b x + a}}{12 \, {\left (b^{2} c + {\left (b x + a\right )} b d - a b d\right )}^{\frac {3}{2}}} - \frac {5 \, {\left (7 \, b^{2} c^{2} {\left | b \right |} - 10 \, a b c d {\left | b \right |} + 3 \, a^{2} d^{2} {\left | b \right |}\right )} \log \left ({\left | -\sqrt {b d} \sqrt {b x + a} + \sqrt {b^{2} c + {\left (b x + a\right )} b d - a b d} \right |}\right )}{4 \, \sqrt {b d} d^{4}} \]
1/12*((3*(b*x + a)*(2*(b^5*c*d^6*abs(b) - a*b^4*d^7*abs(b))*(b*x + a)/(b^4 *c*d^7 - a*b^3*d^8) - (7*b^6*c^2*d^5*abs(b) - 10*a*b^5*c*d^6*abs(b) + 3*a^ 2*b^4*d^7*abs(b))/(b^4*c*d^7 - a*b^3*d^8)) - 20*(7*b^7*c^3*d^4*abs(b) - 17 *a*b^6*c^2*d^5*abs(b) + 13*a^2*b^5*c*d^6*abs(b) - 3*a^3*b^4*d^7*abs(b))/(b ^4*c*d^7 - a*b^3*d^8))*(b*x + a) - 15*(7*b^8*c^4*d^3*abs(b) - 24*a*b^7*c^3 *d^4*abs(b) + 30*a^2*b^6*c^2*d^5*abs(b) - 16*a^3*b^5*c*d^6*abs(b) + 3*a^4* b^4*d^7*abs(b))/(b^4*c*d^7 - a*b^3*d^8))*sqrt(b*x + a)/(b^2*c + (b*x + a)* b*d - a*b*d)^(3/2) - 5/4*(7*b^2*c^2*abs(b) - 10*a*b*c*d*abs(b) + 3*a^2*d^2 *abs(b))*log(abs(-sqrt(b*d)*sqrt(b*x + a) + sqrt(b^2*c + (b*x + a)*b*d - a *b*d)))/(sqrt(b*d)*d^4)
Timed out. \[ \int \frac {x (a+b x)^{5/2}}{(c+d x)^{5/2}} \, dx=\int \frac {x\,{\left (a+b\,x\right )}^{5/2}}{{\left (c+d\,x\right )}^{5/2}} \,d x \]